In methyl alcohol solution,bromine reacts with ethylene (ethene) to yield $BrCH_2CH_2OCH_3$ in addition to $1, 2-dibromoethane$ because

The major products obtained in the following reaction is/are:
$CH_3-CH=CH-C_2H_5 + Br_2 \rightarrow ?$

The predominant product formed when $3$-methyl-$2$-pentene reacts with $HOCl$ is:

The reaction of propene with $HOCl$ proceeds via the addition of

What is the product of the following reaction?

Consider compounds $A$, $B$, and $C$ with the following structural formulae:
$A = CH_3 - CH_2 - CH_2 - CH_2 - CH_2 - OH$
$B = CH_2 = CH - CH_2 - CH_2 - CH_3$
$C = HO - CH_2 - CH_2 - CH(OH) - CH_3$
For the conversion of $B$ from $A$, the reagent $(D)$ required is . . . . . . and the structural formula of the product $(E)$ obtained when $C$ undergoes the same reaction using excess reagent $(D)$ is . . . . . . .